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2.5x=x^2-8
We move all terms to the left:
2.5x-(x^2-8)=0
We get rid of parentheses
-x^2+2.5x+8=0
We add all the numbers together, and all the variables
-1x^2+2.5x+8=0
a = -1; b = 2.5; c = +8;
Δ = b2-4ac
Δ = 2.52-4·(-1)·8
Δ = 38.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.5)-\sqrt{38.25}}{2*-1}=\frac{-2.5-\sqrt{38.25}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.5)+\sqrt{38.25}}{2*-1}=\frac{-2.5+\sqrt{38.25}}{-2} $
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